Web Reference: You can put this solution on YOUR website! . Find the tangent lines to the parabola x^2 = 6y + 10 passing through the point (7,5), which lies outside the parabola. ~~~~~~~~~~~~~~~~ The final equations of the tangent lines are correct in the post by @Alan, but the logic of his solution is unclear to me. I tried to understand it, but failed. You can put this solution on YOUR website! Hi, For this problem we need to put our equation in slope intercept form which is y=mx+b, with m as our slope and b as our y-intercept. Putting the equation in this form will help us to easily identify our slope and y-intercept. Our first step in this problem is to subtract 5x from both sides to get our y term by itself. After doing this we have 6y ... What is the graph of the equation x2 + y2 - 8x + 6y + 24 = 0 This is a circle because and have the same coefficient when on the same side of the equation. We must first get the equation in standard form: Rearrange to get the x terms together and the y terms togethsr. That is, swap the middle two terms: Out to the side or on scratch paper,
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